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X^2-22X=-23
We move all terms to the left:
X^2-22X-(-23)=0
We add all the numbers together, and all the variables
X^2-22X+23=0
a = 1; b = -22; c = +23;
Δ = b2-4ac
Δ = -222-4·1·23
Δ = 392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{392}=\sqrt{196*2}=\sqrt{196}*\sqrt{2}=14\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-14\sqrt{2}}{2*1}=\frac{22-14\sqrt{2}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+14\sqrt{2}}{2*1}=\frac{22+14\sqrt{2}}{2} $
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